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If weQ the clock-to-Q and setup times for each flip-flop are 1 ns, and the delayb assumeDthatin each gate is 1 ns, then the maximum clock frequency for this circuit is:f max =cD11 1 nsD= 200 MHzt c q + 3 × t and + t su 5 nsQfQComputing f max is a basic function of a timing analyzer.
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To operate correctly, the clock frequency is limited by the delay on thelongest path in the circuit. A example for timing analysis.DQIn this example, flip-flops on the left-hand side drive a combinational circuit that generates an output that is later1 nsstored in the flip-flop on the right-hand side. These conditions include, but are not limited to, the maximum clock frequency ( f max ) for whichthe circuit will produce a correct output.Ī simple example of the maximum clock frequency computation is shownin Figure 1.aDQD1 nsbDQfQ1 nscDQ1 nsdDQclockaFigure 1.
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Altera quartus ii logic circuit design software how to#
It demonstrates how to set up timingconstraints and obtain timing information for a logic circuit.The reader is expected to have the basic knowledge of Verilog hardware description language, as well as the basicuse of the Altera Quartus II CAD software.Contents: Using TimeQuestTiming Analyzer1IntroductionThis tutorial provides a basic introduction to TimeQuest Timing Analyzer.